CAT QA · Core idea 3

Counting Lens

Venn diagrams, arrangements, selections and probability are all one skill: drawing the situation so you can count it. Press Play and watch each picture build step by step, or use the arrow keys. Turn on Voice to have it read aloud. Each chapter ends with the CAT trap and the fastest shortcut.

The rules on one card

Everything from the player, compressed. Read it once before each practice burst.

SituationPicture → ruleExample
Sets and Venn diagrams
Any Venn questionFill from the centre outwards: centre → pair-only rooms → single rooms → outsidepair 15, centre 5 → pair-only 10
Two setsA + B − both40 + 30 − 12 = 58
Three setsA+B+C − (pair totals) + centre120 − 37 + 5 = 88
Exactly one / two / threeA+B+C = E1 + 2·E2 + 3·E3; people = E1+E2+E3120 = 61 + 44 + 15
Two-set overlap rangemax = smaller set; min = A + B − total (or 0)60, 50 in 80 → 30 to 50
Max / min of the centreSubtract: E2 + 2·E3 = (A+B+C) − people. Max → E2 as small as allowed. Min → E1 as small as allowed. Then fill and check every room215 − 100 = 115 → 57 and 15
Counting
Choices made together / alternativesAND → multiply · OR → add3 × 2 × 2 = 12 outfits
Order matters (arrange r of n)Slots: n × (n−1) × … = nPr5 × 4 × 3 = 60
Order doesn't matter (select r of n)nCr = nPr ÷ r! · nCr = nC(n−r)60 ÷ 6 = 10
Repeated itemsn! ÷ (p! q! …)BANANA: 720 ÷ 12 = 60
Always togetherGlue into one block × inside orders4! × 2 = 48
Never togethertotal − together, or seat the others and use gaps120 − 48 = 72
Round table / necklace(n−1)! · necklace (n−1)! ÷ 25 people: 24 · beads: 12
Identical items to r peopleDots and bars: (n+r−1)C(r−1); each ≥ 1: hand out first7 to 3: 36 · each ≥1: 15
Grid paths (right / up)A word of R's and U's: (a+b)Cb4 × 3 grid: 35
Handshakes, lines, diagonalsnC2 · diagonals nC2 − n10 people: 45 · octagon: 20
Digits with conditionsFill the fussiest slot first; split cases on 03-digit even, distinct: 328
Probability
Equally likely outcomesfavourable squares ÷ all squaressum 7 on 2 dice: 6/36
Many "yes" cases1 − P(not)≥ one six: 1 − 25/36
Independent eventsMultiply along a tree path, add across paths1/2 × 1/3 = 1/6
At least one in n tries1 − (1 − p)ⁿ4 rolls: 1 − (5/6)⁴ ≈ 0.52
Without replacementShrink the bag after each draw, or nCr ratios5/8 × 4/7 = 5/14
Expected valueBalance point: Σ value × probabilitydie: 3.5

Try it

Three small benches. Each one is a picture from the player that you control.

Seven rooms: push the centre

100 people, each in at least one of P (70), C (65), M (80). Change the rooms until every circle total matches, then try to make the centre as big, then as small, as possible. Tap a room in the picture to pick it.

Dots and bars

Share 5 identical sweets among Asha, Bala and Chetan. Tap any spot to make it a bar; exactly 2 bars are allowed. Find every different sharing.

The 36-square dice board

Pick an event. The board colours the favourable squares. Switch on "not" to see the other side, which is often quicker to count.

Practice: ten questions

Written for this page, easy to CAT level. Each tag names the picture to draw. Give yourself about 2 minutes each; draw first, then calculate.

Q1 · two circles, centre first
Easy

In a class of 50, 32 play chess, 25 play carrom and 9 play neither. How many play both?

Show method
  1. Inside the circles: 50 − 9 = 41 people.
  2. The circles hold 32 + 25 = 57 memberships.
  3. 57 − 41 = 16 people are counted twice, so 16 play both.
Q2 · dice board + "not"
Easy

Two dice are rolled. What is the probability that the product of the two numbers is even?

Show method
  1. The product is odd only when both dice are odd: 3 × 3 = 9 squares.
  2. P(even) = 1 − 9/36 = 3/4.
Q3 · three circles from the centre
Easy–medium

A colony has 200 households. 90 read paper A, 80 read B and 70 read C. 30 read A and B, 25 read B and C, 20 read A and C, and these figures include the 10 that read all three. How many read exactly one paper, and how many read none?

Show method
  1. Centre 10. Pair-only rooms: 20, 15, 10.
  2. A only = 90 − 20 − 10 − 10 = 50. B only = 80 − 20 − 15 − 10 = 35. C only = 70 − 15 − 10 − 10 = 35.
  3. Exactly one = 120. Inside = 120 + 45 + 10 = 175, so none = 25.
Q4 · repeats + glue
Medium

In how many arrangements of the letters of SUCCESS are the two C's next to each other?

Show method
  1. Glue CC into one tile. Tiles: [CC], S, S, S, U, E → 6 tiles.
  2. The S's repeat 3 times; the two C's inside the glue are identical, so no ×2.
  3. 6! ÷ 3! = 120.
Q5 · selection + "not"
Medium

A committee of 4 is chosen at random from 6 men and 4 women. What is the probability that it has at least one woman?

Show method
  1. All committees: 10C4 = 210. All-men committees: 6C4 = 15.
  2. P = 1 − 15/210 = 1 − 1/14 = 13/14.
Q6 · digit slots, split on 0
Medium

How many 4-digit numbers with all digits different are divisible by 5?

Show method
  1. Units slot is the fussy one: 0 or 5.
  2. Units 0: thousands 9 ways, then 8, then 7 → 504.
  3. Units 5: thousands can't be 0 or 5 → 8 ways, then 8, then 7 → 448.
  4. Total 952.
Q7 · round table + glue
Medium

Six people sit around a round table. In how many seatings are two particular people, X and Y, not next to each other?

Show method
  1. All seatings: (6 − 1)! = 120.
  2. Together: glue X and Y → 5 units round the table = 4! = 24, × 2 inside = 48.
  3. Not together: 120 − 48 = 72.
Q8 · dots and bars with minimums
Medium–hard

How many integer solutions does a + b + c = 15 have, with a ≥ 1, b ≥ 2 and c ≥ 3?

Show method
  1. Hand out the minimums first: 1 + 2 + 3 = 6. That leaves 9 to share freely.
  2. 9 dots and 2 bars: 11 spots, choose 2 for bars → 11C2 = 55.
Q9 · grid paths, avoid a point
Hard

You walk from (0, 0) to (5, 4), one unit right or one unit up at each step. How many paths do not pass through (2, 2)?

Show method
  1. All paths: 5 R's and 4 U's → 9C4 = 126.
  2. Through (2, 2): first leg 4C2 = 6, second leg (3 R, 2 U) 5C2 = 10 → 60.
  3. Avoiding: 126 − 60 = 66.
Q10 · seven rooms, push to the max
CAT level

120 people each speak at least one of Hindi, Tamil and Bengali. 80 speak Hindi, 70 Tamil and 60 Bengali. Each of the seven possible combinations of languages is spoken by at least one person. What is the largest possible number who speak all three?

Show method
  1. People: E1 + E2 + E3 = 120. Memberships: E1 + 2·E2 + 3·E3 = 210.
  2. Subtract: E2 + 2·E3 = 90.
  3. Each of the three pair rooms has ≥ 1, so E2 ≥ 3 → 2·E3 ≤ 87 → E3 ≤ 43.
  4. Check E3 = 43, E2 = 4, E1 = 73: pair rooms H-T 2, T-B 1, H-B 1; H only 34, T only 24, B only 15. Every room ≥ 1 and every total matches. Answer 43.